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A student asks, I need to learn about the integral of 1/x.

solutionEdit

Let's consider the indefinite integral,

\int \! {\frac {1} {x}} \,dx \,

The solution is \log(x)+C

Now, let's consider the definite integral,

\int_a^b \! {\frac {1} {x}} \,dx \,

Evaluating the indefinite integral at its limits, we get

Failed to parse (lexing error): \log(x)+C \: \bigg{|}_a^b = \log(b) - \log(a)


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